system 3 eq with 3 unknown w. cos&sin

syms x y r
eq1=((1+cos(2))*x)+((1-cos(2))*y)+((sin(2))*r)==-741.6
eq2=((1+cos(140))*x)+((1-cos(140))*y)+((sin(140))*r)==1768.2
eq3=((1+cos(260))*x)+((1-cos(260))*y)+((sin(260))*r)==-2643.4
result=solve(eq1,eq2,eq3)
vpa(result.x)
vpa(result.y)
vpa(result.r)

what am i doing wrong?

aren't i supposed to get x=-414.722, y=143.579, r=2507.3

[darova]

I got this result

ans =
17200.42119561459346581104722787
ans =
1229.4313261175983169768030796407
ans =
-13774.564011183238331971257084028

Is it wrong?

Answer 1

[Ameer Hamza]

Yes, you are supposed to get that answer. However, you are using sin(), and cos(). In MATLAB, their input is assumed to be in radians. However, it appears that you consider them in degrees. Use sind() and cosd() instead

syms x y r
eq1=((1+cosd(2))*x)+((1-cosd(2))*y)+((sind(2))*r)==-741.6;
eq2=((1+cosd(140))*x)+((1-cosd(140))*y)+((sind(140))*r)==1768.2;
eq3=((1+cosd(260))*x)+((1-cosd(260))*y)+((sind(260))*r)==-2643.4;
result=solve(eq1,eq2,eq3)
vpa(result.x)
vpa(result.y)
vpa(result.r)

Result

ans =
-414.7217490391970254146602927994
ans =
143.57914066956583213246887681175
ans =
2507.2967959133361833043861853089