how to vector with the same length of matrix

2 views (last 30 days)
Hi everyone,
I have to do a vector with the same lenght of matrix. This new vector should contain a package of hour from 1 to 8766, one time that it arrives to end point (8766) it must restarts from 1 and arrives to 8766 and this for the all length of the matrix. I hope to have been clear enough. Thank you.
File = 'D:\Valerio\data\Time_dir_Analysis\Analisys\data\a_ERA5.xlsx';
readFile = xlsread(File);
ERA5 = unique(readFile,'rows');
dt_ERA5 = datetime([ERA5(:,1:4) repmat([0 0],size(ERA5,1),1)]);
tt_ERA5 = timetable(dt_ERA5,ERA5(:,5:end));
  1 Comment
Eva-Maria Weiss
Eva-Maria Weiss on 1 May 2020
I'm not sure, if I got the point. The problem is that size of Matrix is not devisible by 8766?
Maybe the mod function would help b = mod(a,m). Then you can create first your vector by means of repmat function as much as it 'fits'
(floor(size(Matrix,1)/8766))
into the matrix size and then concatenate the 'rest' as 1:b...

Sign in to comment.

Accepted Answer

Ameer Hamza
Ameer Hamza on 1 May 2020
Edited: Ameer Hamza on 1 May 2020
Try something like this
n = size(ERA5,1);
hours_vector = mod((1:n)-1,8766)+1;
hours_vector is like this
hours_vector = [1 2 3 .. .. 8765 8766 1 2 3 .. .. 8765 8766 ..]

More Answers (1)

Peter Perkins
Peter Perkins on 5 May 2020
I'm going to suggest that you stay away from xlsread, and use readtable instead. Putting that together with Am eer's answer, you have
ERA5 = readtable('a_ERA5.xlsx');
ERA5.Time = datetime(ERA5{:,1:3}) + hours(ERA5.Var4);
ERA5 = table2timetable(ERA5(:,5:end));
n = height(ERA5);
ERA5.Hours = hours(mod((1:n)-1,8766)+1)';
head(ERA5)
ans =
8×6 timetable
Time Var5 Var6 Var7 Var8 Var9 Hours
____________________ _____ _____ ______ ______ ______ _____
01-Jan-2005 00:00:00 0.652 8.216 66.211 1.371 -1.466 1 hr
01-Jan-2005 01:00:00 0.645 8.029 65.466 0.559 -2.62 2 hr
01-Jan-2005 02:00:00 0.635 7.915 64.978 -0.359 -3.037 3 hr
01-Jan-2005 03:00:00 0.622 7.81 64.896 -0.861 -2.831 4 hr
01-Jan-2005 04:00:00 0.608 7.702 64.785 -0.94 -2.648 5 hr
01-Jan-2005 05:00:00 0.594 7.593 64.776 -1.396 -2.675 6 hr
01-Jan-2005 06:00:00 0.582 7.484 64.675 -1.944 -2.773 7 hr
01-Jan-2005 07:00:00 0.569 7.369 64.665 -2.103 -2.613 8 hr
I don't actually understand what you want to do with the vector of "hours", but perhaps something like that.

Categories

Find more on Creating and Concatenating Matrices in Help Center and File Exchange

Products


Release

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!