How to stop a rand function from getting the same result in a for loop
1 view (last 30 days)
Show older comments
Hey guys basic question.
I have this code here and i want to print the card deck in a random order:
for x = 1:52
y = randi([1 52]);
if y == 1
fprintf('%s\n','Spade Ace')
elseif y == 2
fprintf('%s\n','Spade 2')
(continues through the whole card deck 1-52)
elseif y == 51
fprintf('%s\n','Clubs Queen')
else
fprintf('%s\n','Clubs King')
end
end
Is there a way I can stop the rand function from comming up with the same number?
0 Comments
Answers (2)
Walter Roberson
on 2 May 2020
cards = {'Spade Ace', 'Spade 2', 'Spade 3' up to 'Clubs Queen', 'Clubs King'};
x = randperm(52);
fprintf('%s\n', cards{x});
No loop needed. rand() not explicitly used (it is used inside of randperm)
Mehmed Saad
on 2 May 2020
Edited: Mehmed Saad
on 2 May 2020
I dont know how to stop rand function from comming up with same number but there is a way you can do that by indexing and removing numbers.
z = 1:52;
x = zeros(1,52);
for i =1:52
y = randi([1 length(z)]);%
x(i) = z(y);
z(y) = [];
end
This will generate random number without repeating them
I stored all the values in x, to check if they are right type following in command window
sort(x)
it will be from 1:52 without any repeatition
0 Comments
See Also
Categories
Find more on Characters and Strings in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!