how to reshape the matrix

i have matrix =001001001111011101111;

and i want to convert it to

001

001

001

111

011

101

111

i know reshape function

matrix=reshape(matrix,[],3);

but it not get the answer which i need

Answer 1

[David Hill]

m =[0 0 1 0 0 1 0 0 1 1 1 1 0 1 1 1 0 1 1 1 1];
a=reshape(m,3,[])';

[Shehab Tarek]

note i want to convert it in 3 colum 7

[Shehab Tarek]

i want to take all 3 bit and save it in 7rows

[Stephen23]

This answer works, I don't see what the problem is:

>> m = [0,0,1,0,0,1,0,0,1,1,1,1,0,1,1,1,0,1,1,1,1];
>> a = reshape(m,3,[]).'
a =
   0   0   1
   0   0   1
   0   0   1
   1   1   1
   0   1   1
   1   0   1
   1   1   1

[Shehab Tarek]

good

but how to make the first line from double matrix to M=[0,0,1,......];

[Stephen23]

Your example:

M=[0,0,1,......];

is also a double matrix. Try it and see:

>> M=[0,0,1];
>> class(M)
ans = double

So instead of a double array you want a double array? In any case, reshape does not change the array type, so whatever type array you have at the start is what you will get at the end.

Answer 2

[Sai Bhargav Avula]

Hi,

Try the following code

convert matrix to char

matrix ='001001001111011101111';
matrix=reshape(matrix,[],3);

Hope this helps!

[Shehab Tarek]

sir this is my output i want to focus in my answer i want it to be like

001 =row1

001 =row2

001 ..

111 ..

011 ..

101 ..

111 row7

take all three bit and save it in 7 row

[Sai Bhargav Avula]

I didnot understand,

if you need a 7*1 array, try this code and operate over the result

matrix ='001001001111011101111';
matrix=string(reshape(matrix,[],3));

This results in a 7*1 string array and can operate over them like

bin2dec(matrix(3));

[Stephen23]

"i want to know why you convert the double matrix to string "

Because Sai Bhargav Avula:

1. did not actually solve the question you asked.
2. did not actually check their output against your expected output.
3. used a pointless data type conversion that does not actually solve either of 1. or 2.

[Sai Bhargav Avula]

From the question

I understood that the input is

matrix= 001001001111011101111;

and not an array.

and from the comment to the other answer I understood that the expected output to be 7*1 martix and not a 7*3 matrix, with each row to be 3 bit value created from matrix variable.

[Stephen23]

"I understood that the input is..."

If the input is either:

• a character vector of '0' and '1' characters, or
• a numeric vector of 0 and 1 values,

then exactly the same operations (reshape and transpose) can be applied to get the requested order.

"I understood that the expected output to be 7*1 martix and not a 7*3 matrix"

This is certainly possible, but does not resolve that your code still put the wrong input elements in the wrong locations. Converting it to a 7x1 string array does not fix that.

>> matrix ='001001001111011101111';
>> matrix=reshape(matrix,[],3) % your code
matrix =
001
011
110
011
011
101
011

Lets compare your output against the requested output given in the original question:

your: original:
001   001
011   001
110   001
011   111
011   011
101   101
011   111

Converting to string will not fix that your code put the incorrect elements in each row.

Discussion of input class and output type conversion are simply distractions from that.

[Shehab Tarek]

thanks in advance sir

[Sai Bhargav Avula]

Thanks for the explanation and clearing my confusion Stephen Cobeldick,

I was thinking more about matrix being a single value(matrix = 001001001111011101111) and not an array( [0 0 1 .....]) and output to be a single colum vector (7*1) and overlooked the expected result .

The answer should have been like what David answered

matrix ='001001001111011101111';
matrix= string(reshape(matrix,3,[])');