how to extract last 3 bits from binary string and then concatenate

Hi, i have an array which is converted into binary string. I want to extract last three bits and then arrange in an array

Y=[123 345 981 345 650]';
%Convert into binary
Y1=dec2bin(Y);
%%%%Out put is
'0001111011'
 '0101011001'
 '1111010101'
 '0101011001'
 '1010001010'

Answer 1

[KSSV]

iwant = Y1(:,8:10)

[lilly lord]

Thanks, It works . How to arrange in a single array like 10100010101....

[KSSV]

iwant(:)'

[lilly lord]

This is the string

    '011'
    '001'
    '101'
    '001'
    '010'

when i use iwant(:)', the out put is

11	1	101	1	10

it skips 0. Is there any way out

[lilly lord]

I need the out put as o11001101001..

[KSSV]

iwant = Y1(:,8:10)' ;
iwant = iwant(:)'

[lilly lord]

Thank u so much.