Displaying cells which have different sizes

Hi everyone. Lets say I have a cell. I tried different ways but I could'nt make it properly.

Y{1,1}=['WATER'] Y{2,1}=2

Y{2,1}=['WATER' 'COKE'] Y{2,2}=3

my code to display these are ;

a=0;
while (a<length(Y))
   a=a+1;
   disp(['#' num2str(a) ':' (Y{a,1}) ' GET-->' mat2str(Y{a,2})])
end

RESULT

'#'    '1'    ':'    'WATER'    'GET-->'    '2'
'#'    '2'    ':'    'WATER' 'COKE'   'GET-->'   '3'

How can I get something like that

#1 : 'WATER' GET--> 2
#1 : 'WATER' 'COKE' GET--> 3

Answer 1

[madhan ravi]

for k= 1:size(Y,1)
    fprintf('#1 : %s GET--> %d\n', Y{k,1}, Y{k,2})
end

[Yasin AHLATCI]

I have an error ;

Error using fprintf

Function is not defined for 'cell' inputs.

[madhan ravi]

clear all
Y{1,1}=['WATER'] 
Y{1,2}=2
Y{2,1}=['WATER', 'COKE'] 
Y{2,2}=3

for k= 1:size(Y,1)
    s = repmat('%s', 1, numel(Y{k,1}));
    fprintf('#1 :',s,' GET--> %d\n', Y{k,1}, Y{k,2})
end

[Yasin AHLATCI]

This doesn't work well for me because for k=2 print is

'WATERCOKE' [3]

but print should be at least 'WATER' 'COKE'

Answer 2

[Image Analyst]

Try this:

Y = {1, 'WATER', []; ...
     1, 'WATER', 'COKE'}

You get:

Y =

2×3 cell array

{[1]} {'WATER'} {0×0 double}

{[1]} {'WATER'} {'COKE' }

The 1,3 cell is still there since you can't have missing elements in an array. Like any array, cell arrays included, you can't have 2 columns in the first row and 3 columns in the second row.

[Yasin AHLATCI]

Hello. I think I misrepresented my situation. My cell is like that. (1x2 cell is 'WATER' 'COKE')

I tried different things for printing it but I couldn't make it. a is my counter.

while (a<size(Y,1))
    a=a+1;
    disp(['#' num2str(a) ':' mat2str(Y{a,1}) ' GET->' mat2str(Y{a,2})]);
end

This works for a=1 Print is;

#1:'WATER' GET->2

But for a=2 I get an error because Y{2,1} is (1x2) cell.

When I didn't use mat2str for Y{a,1} Print is ;

'#'    '2'    ':'    'WATER'    'COKE'    ' GET->'    '3'