Can somebody tell me what is wrong with the following code?

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Hi,
I wrote the following function to build an array of numbers(in the range of 65...74), representing the digits of a number. Here's the algorithm:
function [ y ] = fcn( u )
var y:array[1..10] of byte;
u: longint;
i,nr:byte;
s:boolean;
begin
newu=0;
nr=0;
s=false;
if u<0 then s=true;
while u~=0 do
begin
newu=newu*10+mod(u,10);
u=(u/10);
inc(nr);
end;
for i=nr:1 do
begin
y(i)=mod(newu,10);
newu=(newu/10);
end;
for i=1:nr do
begin
if y(i)==0 then y(i)=65;
if y(i)==1 then y(i)=66;
if y(i)==2 then y(i)=67;
if y(i)==3 then y(i)=68;
if y(i)==4 then y(i)=69;
if y(i)==5 then y(i)=70;
if y(i)==6 then y(i)=71; //At least one END is missing: the statement may begin here.
if y(i)==7 then y(i)=72;
if y(i)==8 then y(i)=73;
if y(i)==9 then y(i)=74;
end
end
y=u;
end
And Matlab gives me the error message stated after the 2 slashes...I am a beginner in Matlab, i can only write code in Pascal language, so I would be glad if someone helped me out.
Thank you, Zoli
  1 Comment
Matt Fig
Matt Fig on 17 Dec 2012
It helps to read the Getting Started section of the doc before jumping in like this. You need to understand basic syntax.

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Accepted Answer

Pedro Villena
Pedro Villena on 17 Dec 2012
num2str(u)
doc num2str

More Answers (1)

John Petersen
John Petersen on 17 Dec 2012
You're syntax is incorrect for Matlab code. First, you don't need to declare your variables. Take out the do's, begin's, and then's. You need an end after every if statement. Comments begin with %, not //. The last for loop can be simplified to
y = y + 65;
  2 Comments
Zoltan
Zoltan on 17 Dec 2012
I rewrote the code. I want to use this as an embedded function in simulink. Everything is OK, except it doesn't wanna use the 'mod' function with the input value(u), because its class is embedded.fi. How can i resolve this problem? Thanks

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