find expression within {}

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Ajay krishna Vasanthakumar
Hello all,
i have to fin {i++;} from the below expression using regexp.can some one help me out?
x = [task_queue[i] > 0 && i<NUM_FLOOR]{i++;}/{a =1;};
i tired using the below regexp
regexp(x,'[^/]\s*{.*}','match')
output : ']{i++;}/{a =1;}'
Thanks,
Ajay
  2 Comments
Rik
Rik on 20 Aug 2020
Although you can do it with regexp, why would you? strfind will do the job here. What do you want to do with the result?
Ajay krishna Vasanthakumar
i just want to to pick the chars inside {.*}.i dont want to pick /{.*} and append some varibales using regexprep.

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Accepted Answer

Rik
Rik on 20 Aug 2020
You were close: you forgot to make the expression lazy, and you forgot you included the close bracket from the sting when excluding the / matched part.
str='x = [task_queue[i] > 0 && i<NUM_FLOOR]{i++;}/{a =1;};';
a=regexp(str,'[^/]({.*?})','tokens');
a{1}
  1 Comment
Ajay krishna Vasanthakumar
Edited: Ajay krishna Vasanthakumar on 20 Aug 2020
Thanks alot rik :)
i did a small correction to the expression
str='x = [task_queue[i] > 0 && i<NUM_FLOOR]{i++;}/{a =1;};';
a=regexp(str,'(?<!/\s*){.*?}','match');
a{1}
just to make sure the before letter is not followed by /.

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