Clear Filters
Clear Filters

Storing values from a for loop

2 views (last 30 days)
HI,
I've noticed this question appears a lot, and I watched the video here :https://www.mathworks.com/videos/storing-data-in-a-matrix-from-a-loop-97493.html, but I haven't been able to figure it out for my own code. The code outputs a value for the area, however doesn't store it as a variable. Any suggestions?
clc;
clear;
x = [ 0 1 2 3 4 5 6 7 8 9 10 11 12];
y = [0 -0.5 -0.8 -0.8 -1 -1.1 -1.2 -1.2 -1.4 -1.2 -1.1 -1 0];
for h0= -2:0.04:1;
h=ones(size(x))*h0;Int=pchip(x,y);xx=linspace(x(1),x(end),500);
yy=y-h0;yyy=pchip(x,yy,xx);gt=yyy<0;
Area =-trapz(xx(gt), (yyy(gt)))
hold off
area(xx, min(ppval(Int,xx), h(1)), h(1), 'EdgeColor', 'none', 'FaceColor', 'b'),grid,
end

Accepted Answer

Alan Stevens
Alan Stevens on 23 Aug 2020
Something like
...
k = 0;
for h0= -2:0.04:1;
k = k+1;
h=ones(size(x))*h0;Int=pchip(x,y);xx=linspace(x(1),x(end),500);
yy=y-h0;yyy=pchip(x,yy,xx);gt=yyy<0;
Area(k) =-trapz(xx(gt), (yyy(gt)));
...etc.
  3 Comments
Hamzah Mahmood
Hamzah Mahmood on 23 Aug 2020
One more follow up question. Currently h0 is being stored as a single variable that is being overwritten, could I use a similar line of code to store that as the range I'm calculating for?
Alan Stevens
Alan Stevens on 23 Aug 2020
You could rearrange the coding as follows:
h0= -2:0.04:1;
for k= 1:length(h0);
h=ones(size(x))*h0(k);Int=pchip(x,y);xx=linspace(x(1),x(end),500);
yy=y-h0(k);yyy=pchip(x,yy,xx);gt=yyy<0;
Area(k) =-trapz(xx(gt), (yyy(gt)));
... etc.
(notice that h0 now becomes h0(k) within the loop) then all values of h0 are available after the loop ends.

Sign in to comment.

More Answers (0)

Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!