Is convhulln function work for N dimensional

5 views (last 30 days)
stuti chug
stuti chug on 11 Sep 2020
Edited: Matt J on 6 Oct 2022
I tried convhulln function on 5 dimentional data. but it shows error in qhullmx "QH6114 qhull precision error: initial simplex is not convex. Distance=-1e+02 The input to qhull appears to be less than 5 dimensional, or a computation has overflowed."
please tell me the limit of N in conhulln fuction. or is their any other function which perform as same as convhulln.
  1 Comment
Pranav Verma
Pranav Verma on 14 Sep 2020
Hi,
Could you please provide a detailed explanation along with the code you have tried so that we can replicate the issue.
Thanks

Sign in to comment.

Answers (1)

Matt J
Matt J on 14 Sep 2020
Edited: Matt J on 14 Sep 2020
The points you are inputting to convhulln do not form a solid shape in R^5. To within numerical precision, they all lie on a line or a hyper-plane or some sub-dimensional shape like that. As a remedy, you could try this FEX submission,
If P are your input points, you can find the vertices V of their convex hull by doing,
[A,b,Aeq,beq]=vert2lcon(P);
V=qlcon2vert(mean(P),A,b,Aeq,beq)
  2 Comments
He Chris
He Chris on 6 Oct 2022
Sorry, I'm stiil confued with the usage of these commands.
How can i replace 'convex = convhulln(map_x);' and obtain the variable value 'convex' with the vert2lcon and qlcon2vert ?
Thanks a lot!!
Matt J
Matt J on 6 Oct 2022
Edited: Matt J on 6 Oct 2022
[A,b,Aeq,beq]=vert2lcon(map_x);
convex=qlcon2vert(mean(map_x),A,b,Aeq,beq)

Sign in to comment.

Categories

Find more on Bounding Regions in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!