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Hi Matlab forums, hope you are all having a good day.

If anyone could spare some time to help me,I have encounted the error called "Unary operator '-' is not supported for operand of type 'function_handle' in for loop function". Does it mean I cant have a negative added onto the functional handle which calculates the drag? I have been giving a image of the specifc formula's and such I am meant to use and told not to change them, so it leads me to a problem in my code. I have tried putting brackets around the drag, so it is -1*(drag) but this does not work with or without brackets. So I'm kind of stuck where the problem is other than line 36 in which matlab tells me. I've attatched my script as a file (renamed just for clarity) and pasted it here. I've also attatched an image of all the formula's and code provided to me which should (hopefully!) assist in diagnosing my error.

I apologise if this type of question has been answered before, I did do a search on the matlab answers page and could only find one problem that was slightly similar to mine.

Any and all help is greatly appreciated forum support, thank you in advance for helping me with my problem!!

clc

clear

%--------------------------------------------------------------------------------------------------------%

p = 1.2; %variables given to me in question

g = 9.81;

m = 77;

c = 1;

a1 = .7;

a2 = 50;

t1 = 50;

t2 = 70;

h0 = 50;

T = .005;

v0 = 50;

tmid = (t1+t2)/2; %formula gives to find what t mid is

%--------------------------------------------------------------------------------------------------------%

A = @(t) 1/2*(a2-a1)*tanh(10.*((t-tmid)/((t2-t1))))+(1/2*(a2+a1));

t = 0:120; %used for plotting x axis

D = @(t) (p*c.*A(t))/2*m; %drag constant

plot(t, A(t), 'b-', 50, .7, 'ro', 70, 50, 'ro') %t1 occurs at 50 seconds in, the area is .7 so I used that as a y co-ordinate and 50 as my x, marking that spot with a red circle.

axis([0 120, .6 70]);

xlabel('Time')

ylabel('Area')

title('Area over Time')

%--------------------------------------------------------------------------------------------------------%

x(1) = 0;, vx(1) = v0;, y(1) = 0;, vy(1) = 0; %initial variables used to start the loop

for n=1 %initialize time index

while 1 %forever while loop

if y(n) > h0, break; end % break when ground is reached

tn = (n-1)*T; %nth time instant in seconds

t(n) = tn; %build time vector, needed for plotting

Dn = D(n).*(tn); %drag constant in time tn

v = sqrt(vx(n)^2+vy(n)^2); %problem tells me to write "no need to save V in an array"- not sure what this means

ax(n) = -Dn * vx(n)*v; %horizontal acceleration

v(n) = sqrt(vx(n)^2+vy(n)^2);

ay(n)= -(D) * vy*v(n)+g;

x(n+1) = x(n)+T*vx(n);

vx(n+1)= vx(n)+T*ax(n);

y(n+1)=y(n)+T*vy(n);

vy(n+1)= vy(n)+T*ay(n);

n = n+1; %updates the index to use N+1, so second round will use 2 for N, as N is defined as 1, N= 1+1, whill use 2 for N in next loop and so on.

end

end

Vc = sqrt(g/D) %equation to be used later

plot(t,ay(t), 'b-', t, ax(t), 'r-'); %axis between 0, where t is less than tg. Roughly set out for now, needs to be worked after loop is fixed.

Michael Croucher
on 17 Sep 2020

You have defined D as a function but in line 36 you are not using it as a function. You have defined it as a function of a variable t so you need to give it some value of t. I'm not sure about what you are calculating but it needs to be something like

-(D(tn)) * vy*v(n)+g;

This causes a different error because D(tn) is a scalar while vy is a vector. Do you mean something like

-(D(tn)) * vy(n)*v(n)+g;

Similar issue with D on line 45.

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