I need you help to convert this equation to matlab code

clear all;

close all;

clc;

tic

%-----------------read image

o=imread('4.2.07.tiff');

[m,n]=size(o);

%----------------random pixel insertion ------

for i=1:m

for j=1:n

if j==1

I(i,j)=randi(i)

else

I(i,j)=o(i,j-1)

end

end

end

this code does'nt work

Answer 1

[drummer]

Looks funny this exercise.

By assigning i to the rand function, it is creating matrices as i increases. So rand(2) creates a 2 x 2 matrix of random values , rand(3) creates a matrix of 3 x 3 and so on...

So rand(i) would be growing in dimension sizes, as i iterates. And not assigning a single random value to the ith element.

@Samiu is correct, I think, regarding the limits of j.

Well, after all, this exercise should give an image with random values only in the first column, and return the original image otherwise?

Check if it is what you're looking for.

- The attached file shows the original in the left, and a zoom in the right to show the random values assigned to the 1st column.

Cheers

clear all;
close all;
clc;
% tic
%-----------------read image
o = imread('pout.tif');
figure
imshow(o);
title('original image');
%%

[m, n] = size(o);
I = zeros(m, n);
%----------------random pixel insertion ------
for i = 1 : m
    for j = 1 : n + 1
        if j == 1
            I(i,j) = rand;
        else
            I(i,j) = o(i,j-1);
        end
    end
end

figure
imshow(I, 'DisplayRange', []);
title('Image I')

Answer 2

[Samiu Haque]

I think the second for loop is supposed to iterate 'n+1' times and not 'n' times. As I(i,j) has the dimension of m*(n+1)