How do I plot the intersection of two inequalities?

I have these two inequalities and I wanna have something like the graph:

I used this code to get this graph, and rotate the axis to show only the xy-plane, but I wanted to represent this area using only the two inequalities.

[x1,x2] = meshgrid(-10:0.02:10,-10:0.02:10);

z = x2 - 8./x1;

cond1 = x1./5 - x2 >= 0;

cond2 = 16 - (x1-5).^2 - x2.^2 >= 0;

cond = cond1.*cond2; z(cond == 0) = NaN;

mesh(x1, x2, z);

[Chen]

Excuse me, what is sense of the cond = cond1.*cond2; z(cond == 0) = NaN ?

Thanks

[Torsten]

NaN values are not plotted.

Answer 1

[Mathieu NOE]

try this :

[x1,x2] = meshgrid(-10:0.02:10,-10:0.02:10);
z = x2 - 8./x1;
cond1 = x1./5 - x2 >= 0;
cond2 = 16 - (x1-5).^2 - x2.^2 >= 0;
cond = cond1.*cond2; z(cond == 0) = NaN;
surf(x1, x2,0*z, z);
shading interp
view(2)

[Mathieu NOE]

hello again

do you mind accepting my answer (if it has fullfiled your expectations ) ? tx

Answer 2

[Ayush Modi]

Hi Gustavo,

As per my understanding, you would like to see the area covered by both the inequalities.

Here is an example showing how you can implement the same:

inq1 = ((1/5)*X) - Y >= 0;
inq2 = 16 - (X-5).^2 - Y.^2 >=0;

% Combine the inequalities
% area = inequality1 & inequality2;
area = inq1 & inq2;

% Create a figure and plot the area
figure;
fill(X(area), Y(area),'b');

Hope this helps!