4th order Runge-Kutta code that can solve for several intial conditions

I created a code that solves differential equations using 4th order runge-kutta method. This code can only take one intial condition. I want to make the code such that it can accept many initial conditions input as a vector and solve for each of them and store all the results in a matrix. Please help.

% Initial conditions
t0=0;
x0=0;
y0=1;
dt=0.1;
tz=10;
t_range= t0:dt:tz;

x_rk=zeros(1,length(t_range));
y_rk= zeros(1,length(t_range));
x_rk(1)=x0;
y_rk(1)=y0;
for i=1:length(t_range)-1
   
   x_rk(i+1)=rk_method_x(x_rk(i),y_rk(i),dt);
   y_rk(i+1)=rk_method_y(x_rk(i),y_rk(i),dt);
end

%% PLots
figure;
plot (t_range, x_rk,'b-o','MarkerSize',5);
hold on
plot (t_range, y_rk,'y-o','MarkerSize',5);


%% Functions
function dxdt= f(x,y)
dxdt= 5*x-3*y;
end 

function dydt=g(x,y)
dydt= -6*x+2*y;
end



function x1=rk_method_x(x0,y0,dt)

k11=f(x0,y0);     
k12=g(x0, y0);
k21=f(x0+0.5*dt*k11,y0+0.5*dt*k12);
k22=g(x0+0.5*dt*k11,y0+0.5*dt*k12);
k31=f(x0+0.5*dt*k21,y0+0.5*dt*k22);
k32=g(x0+0.5*dt*k21,y0+0.5*dt*k22);
k41=f(x0+dt*k31, y0+dt*k32);
k42=g(x0+dt*k31,y0+dt*k32);

x1=x0+dt*((k11/6)+((k21+k31)/3)+(k41/6));
end

function y1=rk_method_y(x0,y0,dt)

k11=f(x0,y0);     
k12=g(x0, y0);
k21=f(x0+0.5*dt*k11,y0+0.5*dt*k12);
k22=g(x0+0.5*dt*k11,y0+0.5*dt*k12);
k31=f(x0+0.5*dt*k21,y0+0.5*dt*k22);
k32=g(x0+0.5*dt*k21,y0+0.5*dt*k22);
k41=f(x0+dt*k31, y0+dt*k32);
k42=g(x0+dt*k31,y0+dt*k32);

y1=y0+dt*((k12/6)+((k22+k32)/3)+(k42/6));

end

Answer 1

[Alan Stevens]

Here's a version:

% Initial conditions
t0=0;
x0=0:0.2:1;
y0=1:0.2:2;
dt=0.1;
tz=1;
t_range= t0:dt:tz;
X = zeros(numel(x0),numel(t_range));
Y = zeros(numel(y0),numel(t_range));
x_rk=zeros(1,numel(t_range));
y_rk= zeros(1,numel(t_range));

for n = 1:numel(x0)
    x_rk(1)=x0(n);
    y_rk(1)=y0(n);

    for i=1:length(t_range)-1
        [x_rk(i+1), y_rk(i+1)]=rk_method(x_rk(i),y_rk(i),dt);
    end
    X(n,:) = x_rk;
    Y(n,:) = y_rk;
    %% PLots
    subplot(numel(x0)/2,2,n)
    plot (t_range, x_rk,'b-o',t_range, y_rk,'y-o','MarkerSize',5);
    grid
    title([num2str(x0(n)),'   ',num2str(y0(n))])
    legend('x','y')
end
disp('X = '), disp(X)
disp('Y = '), disp(Y)

%% Functions
function [dxdt, dydt]= f(x,y)
dxdt =  5*x-3*y;
dydt = -6*x+2*y;
end 

function [x1, y1]=rk_method(x0,y0,dt)

[k11, k12]=f(x0,y0);     
[k21, k22]=f(x0+0.5*dt*k11,y0+0.5*dt*k12); 
[k31, k32]=f(x0+0.5*dt*k21,y0+0.5*dt*k22); 
[k41, k42]=f(x0+dt*k31, y0+dt*k32); 

x1=x0+dt*((k11/6)+((k21+k31)/3)+(k41/6));
y1=y0+dt*((k12/6)+((k22+k32)/3)+(k42/6));
end

[mike kand]

Thank you so much for the help.