How can i set gap between two xlabels created by text

How can i create gap between bottom two labels.

It has two problems:

1) I want to create 11 tick marks on x-axis.

2) I want to create vertical gap between text line of "Angle" and "Number".

Ej_plot=(2.*180.*(jn-1)./Z); % jn=1:11, Z=11
tp=1:11;
figure(3);
        xlim([0 Ej_plot(1,end)]);
        ymin = min(ylim);
        yrng = diff(ylim);
        set(gca, 'XTickLabel', []);
        nrxt = 11;
        lat_txt = cellstr(strsplit(num2str(Ej_plot,'%.2f '),' '));
        text([(Ej_plot(1)-Ej_plot(2))*0.5 Ej_plot], ones(1,nrxt+1)*ymin-0.05*yrng, ['Angle      ' lat_txt],'HorizontalAlignment','center','Rotation',45)
        lng_txt = cellstr(strsplit(num2str(tp),' '));               
        text([(Ej_plot(1)-Ej_plot(2))*0.5 Ej_plot], ones(1,nrxt+1)*ymin-0.1*yrng, ['Number      ' lng_txt],'HorizontalAlignment','center')

Answer 1

[Alan Stevens]

Like so perhaps:

Ej_plot=(2.*180.*(jn-1)./Z); % jn=1:11, Z=11
tp=1:11;
h = figure(3);
        xlim([0 Ej_plot(1,end)]);
        ymin = min(ylim);
        yrng = diff(ylim);
        set(gca, 'XTickLabel', []);
        nrxt = 11;
        lat_txt = cellstr(strsplit(num2str(Ej_plot,'%.2f '),' '));
        text([(Ej_plot(1)-Ej_plot(2))*0.5 Ej_plot], ones(1,nrxt+1)*ymin-0.05*yrng, ['Angle      ' lat_txt],'HorizontalAlignment','center','Rotation',45)
        lng_txt = cellstr(strsplit(num2str(tp),' '));               
        text([(Ej_plot(1)-Ej_plot(2))*0.5 Ej_plot], ones(1,nrxt+1)*ymin-0.15*yrng, ['Number      ' lng_txt],'HorizontalAlignment','center')
        h.CurrentAxes.Position = [0.1300 0.16000 0.7750 0.8200];

[Alan Stevens]

Yes they are. You had

text([(Ej_plot(1)-Ej_plot(2))*0.5 Ej_plot], ones(1,nrxt+1)*ymin-0.1*yrng, ['Number ...

I used ||||

text([(Ej_plot(1)-Ej_plot(2))*0.5 Ej_plot], ones(1,nrxt+1)*ymin-0.15*yrng, ['Number ...

[sachin patel]

Thank you very much... It works...

[sachin patel]

Moreover, it is required to keep text named "Angle" horizontal... How can i do this? But, the angles specified as 0.00, 32.73, etc.. should be inclined. Please reply

[Alan Stevens]

Try

Ej_plot=(2.*180.*(jn-1)./Z); % jn=1:11, Z=11
tp=1:11;
h = figure(3);
        xlim([0 Ej_plot(1,end)]);
        ymin = min(ylim);
        yrng = diff(ylim);
        set(gca, 'XTickLabel', []);
        nrxt = 11;
        lat_txt = cellstr(strsplit(num2str(Ej_plot,'%.2f '),' '));
        text([(Ej_plot(1)-Ej_plot(2))*0.5 Ej_plot], ones(1,nrxt+1)*ymin-0.05*yrng, ['           ',lat_txt],'HorizontalAlignment','center','Rotation',45)
        lng_txt = cellstr(strsplit(num2str(tp),' '));               
        text([(Ej_plot(1)-Ej_plot(2))*0.5 Ej_plot], ones(1,nrxt+1)*ymin-0.15*yrng, ['Number      ' lng_txt],'HorizontalAlignment','center')
        h.CurrentAxes.Position = [0.1300 0.16000 0.7750 0.8200];
        text(-40,ymin-0.05*yrng,'Angle')

[sachin patel]

Thank you very much....