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finding the number of consecutive data

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Hi,
I have a vector of 5000 obeservations containing nan values and prices. How can I tell if this vector contains 60 consecutive prices without any nan interruption?

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Accepted Answer

Thorsten
Thorsten on 1 Feb 2013
This should do the job:
obs1 = observations(1);
Ncons = 1;
for i = 2:numel(observations)
if observations(i) == obs1
Ncons = Ncons + 1;
if Ncons == 60, break; end
else
obs1 = observations(i);
Ncons = 1;
end
end
if Ncons == 60
disp('60 consecutive prices found.')
end

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