matrix store issue for loop iteration

for i=1:3

------------

r=[s m]

The S and M matrix are 1 by 3 matrix. The result "r" matrix is 3 by 2.

The code above is generates combines 2 matrices that is S and M matrix. It generate r matrix output at i=1 upto i =3, but the only last value outputs are stored in "r" matrix that is for i=3.

Answer 1

[KSSV]

r = cell(1,3)  ;
for i = 1:3
    r{i} = [s m]
end

If You feel r will have same size m*p in every iteration, you can initilaize this as a 3D matrix.

r = zeros(m,p,3) ; 
for i = 1:3
    r(:,:,i) = [s m] ; 
end