# how to get the value of x, from this equation: 0.2exp(x)-x^(0.25) = 0

2 views (last 30 days)
Hafizul Sikder on 18 Oct 2020
Answered: mike Croucher on 18 Oct 2020
% I tried with the below steps:
fun = @(x) (0.2*exp(x)-x.^(0.25));
x0 = [1.5,0];
x = fsolve(fun,x0);

#### 1 Comment

Walter Roberson on 18 Oct 2020

Star Strider on 18 Oct 2020
I do not understand what the problem is:
fun = @(x) (0.2*exp(x)-x.^(0.25));
x0 = [1.5,0];
x = fsolve(fun,x0);
xv = linspace(0,2);
figure
plot(xv, fun(xv))
hold on
plot(x, fun(x), 'rx')
hold off
grid
producing:
This appears to work, and provide the solutions you want.

mike Croucher on 18 Oct 2020
That seems to have done the job. I typed your commands and got
x =
1.7492 0.0016
Substituting this into your function gives a vector of results extremely close to 0:
fun(x)
ans =
1.0e-08 *
0.0000 0.1948
Is this what you were hoping for?

R2020b

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