How t generate cone using scattered random point cloud?
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Using the below code, i have geneated sphere. could anyone please guide me how to geneate cone using random scattered point cloud.
I will be very thankful. Thanks in advance to all community members for their cooperation and guidance. Regards
r = randn (10000,3);
r = round(bsxfun(@rdivide,r,sqrt(sum(r.^2,2)))*130);
x = r(:,1);
y = r(:,2);
z = r(:,3);
scatter3(x,y,z)
Accepted Answer
More Answers (1)
Ameer Hamza
on 20 Oct 2020
This is one way. The distribution is non-uniform
h = 2; % height of cone
r = 1; % maximum radius of cross section of the cone
n = 10000;
z = rand(1, n)*h;
t = rand(1, n)*2*pi;
r = interp1([0 h], [0 r], z);
[x, y] = pol2cart(t, r);
scatter3(x, y, z)
23 Comments
M.S. Khan
on 20 Oct 2020
Ameer Hamza
on 20 Oct 2020
First, it generates z coordinates and then, based on z value, calculates x and y coordinates that line on the circle.
M.S. Khan
on 21 Oct 2020
M.S. Khan
on 21 Oct 2020
Ameer Hamza
on 21 Oct 2020
interp1() is a 1D interpolation. This line map value in range 0 to h, to the range 0 to r.
M.S. Khan
on 21 Oct 2020
Ameer Hamza
on 21 Oct 2020
Yes, rand gives uniformly distributed z coordinates. So you get an almost equal number of points for all values of z. But the circumference at the difference value of z is not the same. So at the bottom, the points are densely packed, but at the top, they have a lesser density.
M.S. Khan
on 21 Oct 2020
Ameer Hamza
on 21 Oct 2020
You can use writematrix() to write to a .txt file.
M.S. Khan
on 21 Oct 2020
Ameer Hamza
on 21 Oct 2020
No, the correct syntax is
writematrix([x(:) y(:) z(:)], 'M.txt')
M.S. Khan
on 21 Oct 2020
Ameer Hamza
on 21 Oct 2020
I am glad to be of help!
M.S. Khan
on 21 Oct 2020
M.S. Khan
on 4 Mar 2021
anuradha verma
on 7 Nov 2022
hello sir, can you please help me how to generate unformly distributed points inside a cone.
@anuradha verma This code generates uniform data inside the volume of the half cone with axis parallel to z axis
Rmax = 1; % cone base radius
Zmax = 2; % cone height
N = 1e4; % Number of point
z = rand(1,N).^(1/3);
r = Rmax*sqrt(rand(1,N)).*z;
theta = (2*pi)*rand(1,N);
x = r.*cos(theta);
y = r.*sin(theta);
z = Zmax*z;
scatter3(x,y,z);
axis equal
anuradha verma
on 10 Nov 2022
anuradha verma
on 10 Nov 2022
Sir can you help me with the algorithm for the generation of uniformly distributed points inside the volume of a frustrum. Thanks a lot for your help.
Bruno Luong
on 10 Nov 2022
Please open new question and ideally stop hacking other people's question for cohesion.
anuradha verma
on 10 Nov 2022
Sir I am sorry if i have done anything wrong. I am new to matlab so i don't know much about it. Kindly forgive me.
Bruno Luong
on 10 Nov 2022
Edited: Bruno Luong
on 10 Nov 2022
@anuradha verma, it's not difficult, if you have new question, just click on Ask, or this link:https://mathworks.com/matlabcentral/answers/questions/new
then describe the problem accurately,.
This thread is opened by the author for his problem and it's has been answered.
You question merits a new thread
anuradha verma
on 11 Nov 2022
Thank you sir.
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