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Converting my python code to matlab
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Hi guys.
I've implemented in python convolutional encoder K=7 , r =1/2 and I came from world of python / c++ and rarely I use matlab.
Im trying to convert that code that I've done in python to matlab, could anyone please help me? Im newbie in matlab and Im not using it, rarely I use matlab.
I appreciate your help in advance!! , the attached code down is convolutional encoder K=7 , r =1/2 in python:
import os, math
import collections
G1 = 0x79 # 171 octal
G2 = 0x5B # 131 octal
K = 7
UW = 0x1ACFFC1D
buff = collections.deque(maxlen=K)
def binary(num, length=8):
return format(num, '#0{}b'.format(length + 2))
# Fill the buffer with initial values
for i in range(0, K):
buff.append(0)
bitUW = []
binaryUW = binary(UW, 32)[2:]
for i in binaryUW:
bitUW.append(int(i))
bitG1 = []
bitG2 = []
binaryG1 = binary(G1, K)[2:]
binaryG2 = binary(G2, K)[2:]
for i in range(0, K):
bitG1.append(int(binaryG1[i]))
bitG2.append(int(binaryG2[i]))
convolved = []
def buffIsZero():
for i in range(0, K):
if buff[i] == 1:
return False
return True
for i in bitUW:
buff.appendleft(i)
b0 = 0
b1 = 0
for t in range(0, K):
b0 += bitG1[t] & buff[t]
b1 += bitG2[t] & buff[t]
b0 = b0 % 2
b1 = b1 % 2
b1 = 1 if b1 == 0 else 0
convolved.append(b0)
convolved.append(b1)
while True:
buff.appendleft(0)
if buffIsZero():
break
b0 = 0
b1 = 0
for t in range(0, K):
b0 += bitG1[t] & buff[t]
b1 += bitG2[t] & buff[t]
b0 = b0 % 2
b1 = b1 % 2
b1 = 1 if b1 == 0 else 0
convolved.append(b0)
convolved.append(b1)
#convolved = convolved[:len(convolved)-2]
print convolved
f = open("UW.bit", "w")
t = open("UW_normal.bit", "w")
for s in range(0, 64):
for i in bitUW:
if i == 1:
t.write(chr(0xFF))
t.write(chr(0xFF))
t.write(chr(0xFF))
else:
t.write(chr(0x00))
t.write(chr(0x00))
t.write(chr(0x00))
for i in convolved:
if i == 1:
f.write(chr(0xFF))
f.write(chr(0xFF))
f.write(chr(0xFF))
else:
f.write(chr(0x00))
f.write(chr(0x00))
f.write(chr(0x00))
f.close()
t.close()
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