how to have character replacement

every digit is converted to binary and are grouped with two bits each and i have to replace it with characters.

example A=11000100

i have to replace as

   if    
   11 then 'A'

   00      'C'

   01      'G'

   10      'T'

final result should be a=ACGT

I have written a code it takes long time to get executed

bi = dec2bin(secret,8) - '0';
out = reshape(mat2cell(bi,ones(size(bi,1),1),2*ones(size(bi,2)/2,1))',1,[]);
[r,c]=size(out);
for a = 1:c
  if( out{a} == [0 0])
      out{a} = 'C';
  else
      if( out{a} == [0 1])
          out{a} = 'T';
      else
          if( out{a} == [1 0])
              out{a} = 'A';
          else
              if( out{a} == [1 1])
                  out{a} = 'G';
              end
          end
      end
  end
end

[Jan]

Is A the double 11000100? If so, why do you run DEC2BIN? Or is the "A" in the text equal to "bi" in the code?

Answer 1

[Azzi Abdelmalek]

A='11000100'
s='ACGT'
f=['11';'00';'01';'10']
b=reshape(A,2,[])'
for k=1:numel(s)
  idx=find(ismember(b,f(k,:),'rows'))
  c(idx)=s(k)
end
out=c(:)'

[Sharen H]

Perfect thank you for your help

[Azzi Abdelmalek]

clear 
s='GCTA'
f=['11';'00';'01';'10'];
secret=[70 77];
bi = dec2bin(secret,8);
for p=1:size(bi,1)
  b=reshape(bi(p,:),2,[])';
    for k=1:numel(s)
      idx=find(ismember(b,f(k,:),'rows'));
      c(idx)=s(k);
  end
  out{p}=c(:)';
end
out

[Sharen H]

Sir if it is just reverse how should i do ie the input i have is

s=GCTA

i should replace it as

s = 11000110

Please help

Answer 2

[Honglei Chen]

Sounds like a sequencing problem. You can do it like this

x = '11000100';
idx = bin2dec(reshape(x,2,[]).')+1;
matchset = 'CGTA';
matchset(idx)

[Azzi Abdelmalek]

Typo,

matchset(idx)

instead of

matcheset(idx)

[Honglei Chen]

corrected, thanks.