If clause – if column blank than

Hello guys,

I am encoutering a probem with a script I am currently working on. The idea is that any row of a column named "Anxiety_RESP" that does not contain a value ([ ]) should be replaced with the corresponding value found in a column named "blackscreen_RESP".

So far, I wrote the following code:

for k=1:height(data_pp)

if data_pp.Anxiety_RESP == [];

data_pp.Anxiety_RESP = data_pp.blackscreen_RESP;

else data_pp.Anxiety_RESP = data_pp.Anxiety_RESP;

end

However, the code does not work and the following error is displayed:

Error using ==

Matrix dimensions must agree.

Error in CorrectScript (line 41)

if data_pp.Anxiety_RESP == [];

Thank you in advance!

Best wishes,

Luisa

Answer 1

[Cris LaPierre]

Try isempty instead of ==[].

[Lui Sa]

Thank you very much! Unfortunately, isempty didn't work. It now states the following error:

Error using isempty

Not enough input arguments.

Error in CorrectScript (line 41)

if data_pp.Anxiety_RESP == isempty;

[Cris LaPierre]

Well, you do have to use it correctly. I suggest looking at the documentation page I linked to.

if isempty(data_pp.Anxiety_RESP)

We don't know what Ansiety_RESP is. You may need to do this.

for k=1:height(data_pp)
    if isempty(data_pp.Anxiety_RESP(k))
        ...