How can I write a function that draws a regular polygon with n sides in a polar coordinate plot?

I am unfamiliar with plotting with polar coordinates. Here is what I have so far, which does not work:

function polygon(sides) % Name number of sides of the polygon
degrees=360/sides; % Find the angle between corners in degrees 
radius=ones(1,sides) % Array of ones
theta=0:degrees:360 % Theta changes by the internal angle of the polygon
polar(theta, radius) % Plot
end

Thanks!

[Danielle Wojeski]

%First you need to define the sides variable.

sides=input('input the number of sides you want;, ')

Then you need to make sure the radius and the theta match in size. If your theta starts at 0 it will always be one size bigger then your radius. So instead make it a 1.

It should look like this...

function polygon(sides) % Name number of sides of the polygon
sides = input('input the number of sides you want;, ');
degrees = 360./sides; % Find the angle between corners in degrees 
r = ones(1,sides) % Array of ones
theta = 1:degrees:360 % Theta changes by the internal angle of the polygon
polar(theta, r) % Plot
end

Answer 1

[Azzi Abdelmalek]

close
sides=5
degrees=2*pi/sides 
theta=0:degrees:360-degrees 
radius=ones(1,numel(theta)) 
polar(theta,radius)

[gm76]

Thanks so much, this works! Why is it that degrees seems to be defined in radians, (2*pi/sides) but is then subtracted from 360?

[Azzi Abdelmalek]

I can't for the moment explain this, It was an error, it should be

sides=9
degrees=2*pi/sides 
theta=0:degrees:2*pi
radius=ones(1,numel(theta)) 
polar(theta,radius)

Answer 2

[Carson Cooper]

This gives a better output than those above

function polygon(sides)

sides = input('input the number of sides you want;, ');

radians = (2*pi)./sides;

r = ones(1, sides);

theta = 1:radians:2*pi;

polar(theta, r)

end

[Gigglemello]

Thank you for this! But, why did I get an open-ended polygon? How do I close it?

[Sophie]

sides = input('input the number of sides you want;, ');

radians = (2*pi)./sides;

r = ones(1, sides+1);

theta = 0:radians:2*pi;

polar(theta, r)

This seemed to fix the openness of the polygon. I don't understand why tho :3

[Anders Bray]

theta includes 0 as the first step making it an 1x(sides+1) that is why have to accomidate.

[debashish panda]

for n=3:1:6
    subplot(2,2,n-2)
    polygon(n)
end

function polygon(sides)

radians = (2*pi)./sides;
r = ones(1, sides+1);
theta = 0:radians:2*pi;
polar(theta, r)
end