Output of function not variable I assign

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Kyle
Kyle on 17 Mar 2013
When I run this function I want that vector to be called u so I can use it in another script file. Instead it calls it "ans" which I can't use. What is going on? Here is the function, just run it for n=4.
function [u]=finitevolume_KG(n)
%n is the number of volumes
delta_x = 1/n;
A=zeros(n-1);
A(1,1)=1;
A(1,2)=-1;
for i=2:n-2
A(i,i-1)=-1;
A(i,i)=2;
A(i,i+1)=-1;
end
for i=n-1
A(i,i-1)=-1;
A(i,i)=2;
end
f=ones(n-1,1);
f_x=((delta_x)^2)*f;
u = (A)\(f_x);

Answers (2)

per isakson
per isakson on 17 Mar 2013
Edited: per isakson on 18 Mar 2013
Try the call
u = finitevolume_KG( 4 )
and make it a habit to end your functions with the keyword "end".
  2 Comments
Jan
Jan on 18 Mar 2013
I still omit the trailing "end" to support the small part of Matlab 6.5 users.
per isakson
per isakson on 19 Mar 2013
Yes, but "end" kind of indicates the end of the workspace of the function.

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Jan
Jan on 18 Mar 2013
Some simplifications:
function u = finitevolume_KG(n)
%n is the number of volumes
delta_x = 1/n;
A = zeros(n-1, n-1);
A(1,1) = 1;
A(1,2) = -1;
A(2:n-2, 1:n-3) = -1;
A(2:n-2, 2:n-2) = 2;
A(2:n-2, 3:n-1) = -1;
A(n-1, n-2) = -1;
A(n-1, n-1) = 2;
u = A \ (delta_x ^ 2 * ones(n-1, 1));

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