how to creating matrix h 4x2 with some rules
Show older comments
I have some trouble when creating matrix 4x2 with rules like below. the first column are integer and the other column are random number. I already create the syntax below.
for ii = 1:8,
nilai = mod(ii,2);
if nilai == 0
x(ii) = 0.95 + (1.05-0.95)*x(ii);
elseif nilai ~= 0
x(ii) = round(3 + (30-3)*x(ii));
elseif nilai ~= 0
x(ii) = 0.01 + (0.055-0.01)*x(ii);
else
x(ii) = 1.0 + (1.15-1.0)*x(ii);
end
end
x = reshape(x,4,2)';
but the result are
??? Error using ==> reshape
To RESHAPE the number of elements must not change.
anyone can help me with this problem..? any solutions are very welcome..
thank you.
Accepted Answer
More Answers (1)
Image Analyst
on 21 Mar 2013
I got a different error message due to x not being predefined and your new x(ii) depends on your old x(ii). When I predefined x, it ran with no errors:
x = zeros(1, 8);
for ii = 1:8
nilai = mod(ii,2);
if nilai == 0
x(ii) = 0.95 + (1.05-0.95)*x(ii);
elseif nilai ~= 0
x(ii) = round(3 + (30-3)*x(ii));
elseif nilai ~= 0
x(ii) = 0.01 + (0.055-0.01)*x(ii);
else
x(ii) = 1.0 + (1.15-1.0)*x(ii);
end
end
x = reshape(x,4,2)'
In the command window:
x =
3 0.95 3 0.95
3 0.95 3 0.95
2 Comments
Noru
on 21 Mar 2013
Image Analyst
on 21 Mar 2013
% make the value of the 3rd column like 2nd
x(:,3) = x(:,2);
% make the value of the 3rd column like 4th
x(:,3) = x(:,4);
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!