Counting coins - bwconncomp returns only one object
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Flatfoot
on 24 Dec 2020
Commented: Image Analyst
on 24 Dec 2020
I'm doing an exercise using the Image Processing Toolbox and the 'coins.png' image built-in in MATLAB.
In the last line of the code before the function, when I call the function bwconncomp, I returns only one object instead of 14.
filtsize = 85;
im1 = imread('coins.png');
[r,c] = size(im1);
im2 = imread('eight.tif');
[r2,c2] = size(im2);
filtsizeh = floor(filtsize/2);
im = zeros(r+r2+filtsize,c+filtsize);
im(filtsizeh+1:filtsizeh+r+r2,filtsizeh+1:filtsizeh+c) = [im1;255-im2(:,1:c)];
[r,c] = size(im);
imagesc(im);colormap(gray);title('test image');axis equal;
msk=[]; msk_dil=[]; msk_dil_erd=[]; centroid=[]; component_size=[];
[msk,thrsh] = OtsuThreshold(im);
figure; imagesc(msk); colormap(gray); title('Otsu'); axis equal;
msk_dil = im<=88;
figure; imagesc(msk_dil); colormap(gray); title('Dilated'); axis equal;
msk_dil_erd = imerode(msk_dil,ones(7,7));
figure; imagesc(msk_dil_erd); colormap(gray); title('Eroded'); axis equal;
comps = bwconncomp(msk_dil_erd);
%%
function [msk,thrsh] = OtsuThreshold(img)
histogram = imhist(img);
thrsh = otsuthresh(histogram);
thrsh = thrsh*255;
msk = img > thrsh;
end


Someone able to help?
0 Comments
Accepted Answer
KALYAN ACHARJYA
on 24 Dec 2020
Edited: KALYAN ACHARJYA
on 24 Dec 2020
Please note it consider white pixels as objects, hence it shows 1. Have you check the "msk_dil_erd" image. May be you complement the image, check it carefully-
figure; imagesc(~msk_dil_erd); colormap(gray); title('Eroded'); axis equal;
comps = bwconncomp(~msk_dil_erd)
More: This may show a different result, as some coins may still be interconnected., do the image erode with proper structuring element to get disconnected coins (also note on the outer space may consider the 1 object)
More Answers (1)
Image Analyst
on 24 Dec 2020
So it doesn't work because of this line:
im(filtsizeh+1:filtsizeh+r+r2,filtsizeh+1:filtsizeh+c) = [im1;255-im2(:,1:c)];
c is the number of columns in im1, then you're trying to use it to index into im2, which does not have as many columns as im1, and it throws the error.
Index in position 2 exceeds array bounds (must not exceed 308).
Error in test5 (line 17)
im(filtsizeh+1:filtsizeh+r+r2,filtsizeh+1:filtsizeh+c) = [im1;255-im2(:,1:c)];
But I noticed you accepted the answer so I guess you got it figured out. Let us know if that's not the case and I need to fix anything.
2 Comments
KALYAN ACHARJYA
on 24 Dec 2020
Sir, I executed the code, it runs without any error. (Considering the same image name)
Image Analyst
on 24 Dec 2020
Yes, but if they're different sized images like he used, then it throws an error.
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