Taylor expansion calculation of exp(x^2)
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aroj bhattarai
on 30 Dec 2020
Commented: aroj bhattarai
on 1 Jan 2021
Dear Matlab users and experts,
I am aware that the exponential function is standarized as "exp" in Matlab . However, I need to calculate the function value exp(x^2) adjusting the (N) terms in the power series. Can anyone recommend the correct method to compute the function exp(x^2)?
My approach:
x = -3.0:0.1:3.0;
N = 12;
Taylor_p2 = 0;
for n = 0:N
Taylor_p2 = Taylor_p2 + (x.^(2.0.*n))./(factorial(n)); % Taylor_p2 = exp(x^2)
end
isn't giving me the desired value. I am using R2020b Matlab version.
Many thanks in advance.
Bhattarai
0 Comments
Accepted Answer
Ameer Hamza
on 30 Dec 2020
Edited: Ameer Hamza
on 30 Dec 2020
The formula for taylor series is correct. Just increase the number of terms.
x = -3.0:0.1:3.0;
N = 12;
Taylor_p2 = 0;
for n = 0:N
Taylor_p2 = Taylor_p2 + (x.^(2.0.*n))./(factorial(n)); % Taylor_p2 = exp(x^2)
end
p2 = exp(x.^2);
err = norm(p2-Taylor_p2);
plot(x, p2);
hold on
plot(x, Taylor_p2, '*')
Result
>> err
err =
9.1544e-05
3 Comments
John D'Errico
on 31 Dec 2020
This folllowup question about other powers of x in the exponential is completely different from your original one, because the function is different. What happen when x is negative, and you try raising that number to non-integer powers? Should you not expect a complex number as a result? The warning message you got was from plot, when you told it to plot complex numbers. The bug is in your code, and how you handle complex results.
Finally, I would point out that this function is expected to be poorly convergent for values of x where abs(x) grows greater than 1.
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