replacing loop with cell of index values

I don't know how to explain with words what I'm trying to do, so here is an example

%I have an array of values

s = [1:100];

% and I have a cell array of different index values

c{1} = 1;

c{2} = 1:5;

c{3} = 2:2:10;

% I would like a cell array t, where

t{1} = s(c{1});

t{2} = s(c{2});

% etc.

% I can do this with a loop, but I'm wondering if there is a way to do this without a loop as my set of indices are large.

Answer 1

[Stephen Cobeldick]

s = 1:100;
c{1} = 1;
c{2} = 1:5;
c{3} = 2:2:10;
out = cellfun(@(x)s(x),c,'uni',0);
out{:}

ans = 1

ans = 1×5

1 2 3 4 5

ans = 1×5

2 4 6 8 10

A well-written (i.e. correctly preallocated, etc.) loop will be faster.

[Catherine]

Thank you. Good to know that the loop might be faster.