evaluate expression

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omnia
omnia on 12 May 2011
I have equation y=x*exp( (1-y)/(A*y)*B ) where A nd B constants in my program. I have a vector values for x. How can I evaluate y to plot y versus x ?

Accepted Answer

Andrei Bobrov
Andrei Bobrov on 12 May 2011
ezplot(['y-x*exp( (1-y)/(' num2str(A) '*y)*' num2str(B) ')'],[x(1) x(end)])
more
As = ...;
Bs = ...;
y = zeros(size(x));
for j = 1:length(x)
y(j) = fzero(@(y)y-x(j).*exp( (1-y)./(As*y)*Bs ),1);
end
plot(x,y);
  2 Comments
John D'Errico
John D'Errico on 12 May 2011
It is generally not a good idea to convert the numeric values into strings to then pass into ezplot. This loses precision. Far, far better is to use an anonymous function here.
omnia
omnia on 13 May 2011
Thank you alot

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More Answers (1)

Andrew Newell
Andrew Newell on 12 May 2011
It would be simpler to provide y and solve for x:
y = -1:0.01:1;
x = y.*exp(- (1-y)./(A*y)*B );
In plotting this, you have to be careful because x goes to Inf or -Inf as y approaches zero from below:
I = y < 0 & abs(x) < 10;
plot(x(I),y(I))
hold on
I = y > 0 & abs(x) < 10;
plot(x(I),y(I))
  1 Comment
omnia
omnia on 13 May 2011
yes I know it is easier to provide y and solve for x, but I don't have y. The input to my file is x values.

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