how to plot linear regression ?
4 views (last 30 days)
Show older comments
i want to do linear regression for : log(vp)=A-B/(T+273.15) !!
vp = [ 1 5 10 20 40 60 100 200 400 760]
T = [-36.7 -19.6 -11.5 -2.6 7.6 15.4 26.1 42.2 60.6 80.1]
y = log10(vp);
x = 1./(T+273.15);
% fit the polynomial
p = polyfit(x,y,1)
% p = -2035.33 8.75201
y=polyval(p,x)
plot(T,y,'or',T,vp,'b')
xlabel('T (C)')
ylabel('vp (mm Hg)')
0 Comments
Accepted Answer
Star Strider
on 8 Feb 2021
Try this:
figure
plot(T,vp,'or',T,10.^y,'b')
xlabel('T (C)')
ylabel('vp (mm Hg)')
The rest of the code is unchanged.
2 Comments
More Answers (1)
the cyclist
on 8 Feb 2021
Edited: the cyclist
on 8 Feb 2021
You should plot
plot(T,10.^y,'or',T,vp,'b')
because you did the regression on log10(y), not y itself.
vp = [ 1 5 10 20 40 60 100 200 400 760]
T = [-36.7 -19.6 -11.5 -2.6 7.6 15.4 26.1 42.2 60.6 80.1]
y = log10(vp);
x = 1./(T+273.15);
% fit the polynomial
p = polyfit(x,y,1)
% p = -2035.33 8.75201
y=polyval(p,x)
plot(T,10.^y,'or',T,vp,'b')
xlabel('T (C)')
ylabel('vp (mm Hg)')
Also, it looks like you plotted the data as a line, and the fit as individual circles. I expect you want the opposite, which is more conventional.
See Also
Categories
Find more on Linear and Nonlinear Regression in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!