Subscripted assignment dimension mismatch ?
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Hi,
I would like to fill the columns of an array of unknown number of rows with elements from a known vector; such as:
for i=1:100
vector= {bunch of calculations to find vector}
array(:,i)= vector
end
where vector is a N x 1 vector, and we obviously don't know the maximum number of rows of array. What is a computationally efficient way of doing this?
Thanks.
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Answers (1)
Walter Roberson
on 21 May 2013
for i = 100: -1: 1
vector= {bunch of calculations to find vector}
array(:,i)= vector
end
Provided, of course, that the vector is the same length for all entries.
Alternately,
i = 1;
vector= {bunch of calculations to find vector}
array = zeros(length(vector), 100);
array(:,i) = vector
for i = 2 : 100
vector= {bunch of calculations to find vector}
array(:,i)= vector
end
2 Comments
Walter Roberson
on 21 May 2013
Edited: Walter Roberson
on 21 May 2013
If the vector length is not the same for all entries then you have a difficulty: what to do with the unoccupied locations if you are using a numeric array?
Urrr... where you wrote {bunch of calculations to find vector} was that intended to indicate creating a cell array?
Anyhow...
array = cell(100,1);
for i=1:100
vector= ... %bunch of calculations to find vector in numeric form
array{i} = vector;
end
This creates a cell array in which each entry is the proper length
or
array = NaN(Maximum_length_vector, 100);
for i=1:100
vector= ... %bunch of calculations to find vector in numeric form
array(1:length(vector),i) = vector;
end
This would leave NaN in the unused positions of a numeric array
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