addition , subtraction

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nand mourya
nand mourya on 19 May 2011
[EDIT: 20110519 14:45 CDT - reformat - WDR]
Hi, I need help in coding the following example.. thanks
S is (mXn) matrix and d is (mX1) array
S(1,:) = [0 0.2 0.3 0.5 0.6 0.7 0.72 0.75 ...... 1 ]
for example length(S(1,:)) = odd (lets say 7)
d(1)= S(1,1) + (S(1,3)-S(1,2))+(S(1,5)-S(1,4))+(S(1,7)-S(1,6))
...and so on...
if length(S(1,:)) = even(lets say 8)
d(1)=S(1,1) + (S(1,3)-S(1,2))+(S(1,5)-S(1,4))+(S(1,7)-S(1,6))
i.e. neglect S(1,8)
I want to run this program in a loop for entire S matrix and find the array d

Accepted Answer

Walter Roberson
Walter Roberson on 19 May 2011
d = Sum(S(:,1:2:end),2) - Sum(S(:,2:2:end-1),2)
  2 Comments
Andy
Andy on 19 May 2011
Ninja'd! Walter, you need lower case sums.
Walter Roberson
Walter Roberson on 19 May 2011
Good point, Andy. I've been flipping between programming languages too much.

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