Preallocating the size of a matrix which concatenates horizontally matrices in a for loop
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How can I preallocate matrix t:
t=[];
for i=1:3;
a=randi(10,3,2);
t=[a t];
end
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Accepted Answer
the cyclist
on 16 Jun 2013
Like this. (I also parameterized so it would be easier to see how this generalizes.)
m=3;
n=2;
t = zeros(m,m*n);
for i=1:m;
a = randi(10,m,n);
t(:,n*(i-1)+1:n*i) = a;
end
You don't need the intermediate variable, either:
m=3;
n=2;
t = zeros(m,m*n);
for i=1:m;
t(:,n*(i-1)+1:n*i) = randi(10,m,n);
end
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