iteratively changing a value within a line of code based on the output

I am having issues with the lines presented in the second section of the code below. I think it is inefficient to type it like this. Normally I would place all of the xn0,xn1...xn8 values into an array and then call the correspodning elements to be summed with the corresponding tc1 elements. However, I only know xn0 (although i can compute the rest) and therefore do not know how to approach this problem. Any help is greatly appreciaated.

(Sorry if the title was misleading I didnt know what to call this question. I also struggled to word it and hope the code can clarify my issue )

h1 =[0.6,0.617725,0.63545,0.653175,0.6709,0.688625,0.70635,0.724075];
h2 = [0.617725,0.63545,0.653175,0.6709,0.688625,0.70635,0.724075,0.7418];
fh1 = [276.981849374449,256.563282315502,233.338198927531,206.859609346339,176.571144087757,41.772230732072,101.568977010934,54.8034249508092]
fh2 = [256.563282315502,233.338198927531,206.859609346339,176.571144087757,41.772230732072,101.568977010934,54.8034249508092,-0.0508040527532690]
tc1 = ((h2-h1)./2).*(fh2+fh1);
xn0 = 0
%% I would prefer to be able to loop this such that xn1 replaces xn0, and then this is replaced by xn3 ,all while the column number is changing to 
xn1 = xn0+tc1(:,1);
xn2 = xn1+tc1(:,2);
xn3 = xn2+tc1(:,3); 
xn4 = xn3 +tc1(:,4);
xn5 = xn4 + tc1(:,5);% Continues on after this line  (for each of the 8 columns in tc1)
%% My problem with using for loop 
for i = [1:1:8]
    xn1(i) = xn0+tc1(:,i) % This would just add each element from tc1 to xn0.  I dont know how to get xn0 to change to xn1, and then that to the next etc  
end

Answer 1

[Deepak]

Hi James, from my understanding, you have an array named “tc1” of size 8, that stores double values. Now, you want to create another “xn” array whose values depend on “tc1” array, and on previous index values of “xn” array.

To build the “xn” array, we can first initialize it with a default value. Then, we can iterate over it to calculate the values at each index. This way, we do need to fill in all the “xn” values manually.

Below is the MATLAB code for the same:

xn = zeros(1, length(tc1) + 1); % Initialize an array 
xn(1) = 0; % Initial value for xn0 

for i = 1:length(tc1) 
    xn(i + 1) = xn(i) + tc1(i); 
end 

Attaching the documentation of methods used for reference:

https://www.mathworks.com/help/matlab/ref/zeros.html

I hope this fixes the problem.