Exiting if condition when condition is not met, but continue for loop

Hi I have a if condition nested in a for loop that looks something like this. So there will be times when sum(A) does not meet the condition and the error will appear. However, I want the for loop to still loop the next iteration, ie if condition is not met at 6th loop, error should be displayed and the for loop moves on to the 7th one.

I tried the continue function, but it does not prompt the for loop to continue when condition is not met. Which function is recommended in this case/how can the code be improved?

Many thanks!

for k = 1:10
code 
    if sum(A)> 10
code 
    else 
        disp(error)
        continue
    end
code
end

[Jan]

I do not know any programming language, which has an "if loop". Loops are built by for and while only (and GOTO...).

[Cside]

i meant ifelse condition/statement. Thank you!

Answer 1

[Jan]

The continue statement does proceed the loop, exactly as you have described your needs. Why do you think, that "it does not prompt the for loop to continue"?

for k = 1:7
    fprintf('\nk=%d:', k)
    if mod(k, 3) == 0
       fprintf('  mod(%d,3)=0 ', k)
    else 
       fprintf('  Not matching')
       continue
    end
    fprintf('  final part\n')
end

k=1:

  Not matching

k=2:

  Not matching

k=3:

  mod(3,3)=0 

  final part

k=4:

  Not matching

k=5:

  Not matching

k=6:

  mod(6,3)=0 

  final part

k=7:

  Not matching

A nicer version:

for k = 1:7
    fprintf('\nk=%d:', k)
    if mod(k, 3) ~= 0
       fprintf('  Not matching')
       continue
    end
    
    fprintf('  mod(%d,3)=0 ', k)
    fprintf('  final part\n')
end

or

for k = 1:7
    fprintf('\nk=%d:', k)
    if mod(k, 3) == 0
       fprintf('  mod(%d,3)=0 ', k)
       fprintf('  final part\n')
    else 
       fprintf('  Not matching')
       % No CONTINUE needed here
    end
end

[Cside]

Thank you so much, i managed to debug it