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How do I create function that is defined by itself?

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Hjalmar Stenberg
Hjalmar Stenberg on 22 Apr 2021
Answered: Pratyush Roy on 27 Apr 2021
I need help creating this function. I have defined x(t) as
x = @(t) t.*((t>=0)&(t<1))+(0.5+0.5.*cos(2*pi*t)).*((t>=1)&(t<2))+(3-t).*((t>=2)&(t<3));
The end result should look like this

Answers (1)

Pratyush Roy
Pratyush Roy on 27 Apr 2021
Hi,
As per the equations mentioned above, the function is a periodic one with a period of 4. You can refer to code snippet below to generate a periodic function:
x = @(t) t.*((t>=0)&(t<1))+(0.5+0.5.*cos(2*pi*t)).*((t>=1)&(t<2))+(3-t).*((t>=2)&(t<3))
duration = T;
t = 0:0.5:T; %Time interval is chosen as 0.5 in this case, user can change this value.
y = x(mod(t,4));%Period of 4
plot(t,y)
Hope this helps!

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