Retime data aggregation for ID
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Hello everyone,
I'm going to calculate the monthly average of daily temperatures grouping by sensor using retime function. At the moment I'm trying to select each sensor with a loop and then apply the retime function, but I have to calculate six million rows so I would like to avoid a loop to speed up the calculation
I give an example:
Time = datetime({'18-feb-2021';'19-feb-2021';...
'01-mar-2021';'04-mar-2021';'18-feb-2021';...
'19-feb-2021';'01-mar-2021';'04-mar-2021'});
Temp = [56.82;62.72;64.52;63.81;63.45;59.7;60.27;61.32];
Sensor = [12;12;12;12;13;13;13;13];
TT = timetable(Time,Sensor,Temp);
Current code:
uni_sensor = unique(Sensor);
monthly_ds = timetable;
parfor kk = 1:length(uni_sensor)
index_retime = find(TT.Sensor == uni_sensor(kk));
sensor_retime = TT(index_retime,:);
monthly_data = retime(sensor_retime(:,2), 'monthly', 'mean');
data_sensor_retime = array2table(repmat(uni_sensor(kk), size(monthly_data, 1),1), 'VariableNames', "Sensor" );
monthly_sub_id = [monthly_data, data_sensor_retime];
monthly_ds = [monthly_ds; monthly_sub_id];
end
Desired output:
Time = datetime({'feb-2021';'feb-2021';...
'mar-2021';'mar-2021'});
Temp = [59.77;61.575;64.165;60.795];
Sensor = [12;12;13;13];
TT_out = timetable(Time,Sensor,Temp);
Thanks in advance,
Gianluca
Accepted Answer
More Answers (1)
Eric Sofen
on 4 May 2021
0 votes
Another approach is to unstack the timetable based on the sensor ID, so you'd have a wide timetable with separate variables temp_12, temp_13, ..., then apply retime to that without a need for grouping. I don't know if it would be faster than Marco's findgroups approach (which is quite clever), and having the sensor IDs embedded in the table variable names may or may not be useful in the long run, but it's yet another way to tackle this problem.
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