Why sym2poly function converts a random string to s polynomial?
1 view (last 30 days)
Show older comments
Why sym2poly function converts a random string ('cacssd' for example) to [1 0] polynomial?
syms s
rt='cacd';
num=sym(rt);
snum=sym2poly(num)
I want to handle an error for this but unfortunatly there is no error. Any idea?
0 Comments
Accepted Answer
sadel
on 30 May 2011
6 Comments
Walter Roberson
on 30 May 2011
If that's what you wanted, they just use
if ismember('s',symvar(insertfunction))
snum = sym2poly(sym(insertfunction));
else
warn='Invalid variable'
end
However, the presence of s as a free variable in insertfunction does not establish that insertfunction codes a polynomial.
More Answers (1)
Paulo Silva
on 29 May 2011
The result [1 0] means that there's a symbolic variable with 1 for it's coefficient, the polynomial is:
1*cacd+0
6 Comments
Walter Roberson
on 30 May 2011
casd *does* have "the type of a polynomial", just as much as 1*x+0 does.
Perhaps what you want is to restrict to certain variables and then use coeff() or coeffs() to detect whether those variables occur.
See Also
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!