Solving composite equations with symbolic toolbox
    5 views (last 30 days)
  
       Show older comments
    
    Nicholas Davis
 on 1 Jun 2021
  
    
    
    
    
    Commented: Sulaymon Eshkabilov
      
 on 2 Jun 2021
            Hi all,
I have a very simple code written to solve for two variables within two equations. My main variables are A and B, which are renamed to AR and BR later in the program. My constants are w, g, alphaL, and p. The initial equation is quadratic and thus will have two answers. I want each of these answers to be plugged into a new equation, a cubic equation, to therefore produce 6 differing solutions. I am not sure how to do this via symbolic toolbox, so any help would be seriously appreciated. Thanks!
syms A B w g alphaL p % w = (mu - V0)
eqn = B*(A + B)*(2*w - g*(A + 2*B)) - alphaL^2 == 0;
AR = solve(eqn,A);
neqn = -4*(B - p)*(AR + B - p)*(2*w - g*(AR + 2*B + p)) == 0;
BR = solve(neqn,B);
3 Comments
  John D'Errico
      
      
 on 1 Jun 2021
				You CAN do it that way, at least, in this case, you can. However, the symbolic toolbox is better used to solve the two equations simultaneously. It has no problem with understanding there should be 6 solutions. @Sulaymon Eshkabilov shows how to do that.
Accepted Answer
  Sulaymon Eshkabilov
      
 on 1 Jun 2021
        Hi,
Here is the corrected code with the symbolic solutions (A, B) of the two equations:
clearvars
syms A B w g alphaL p AR
eqn1 = B*(A + B)*(2*w - g*(A + 2*B)) - alphaL^2 == 0;
eqn2 = -4*(B - p)*(AR + B - p)*(2*w - g*(AR + 2*B + p)) == 0;
SOL = solve(eqn1, eqn2,A, B);
A_solution=SOL.A;
B_solution=SOL.B;
Good luck.
2 Comments
  Sulaymon Eshkabilov
      
 on 2 Jun 2021
				Most welcome!
The last two lines are separation of solutions of A and B variables.
More Answers (0)
See Also
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!


