Matlab less than comparison
3 views (last 30 days)
Show older comments
The Matlab documentation is confusing me.
I want to test each cell in a specific row of an array (cA). If that cell has a value that is less than a constant (NC), then change the cell value to the constant. Here's what I have:
if cA(i+1,:) <NC;
cA(i+1,:)=NC;
end;
Is this correct? I'm confused because the documentation says that the result of the "<" statement is just a logical vector (in this case) of 1 and 0 depending upon whether the comparison is true or false.
1 Comment
Stephen23
on 20 Jun 2021
Although you asked about the le operator, by far the simplest and most efficient solution to your problem is actually this:
cA(i+1,:) = max(NC,cA(i+1,:))
Answers (2)
Chunru
on 20 Jun 2021
The correct way should be:
cA(i+1,:) = max(cA(i+1,:), NC);
or
idx = cA(i+1,:) <NC;
cA(i+1, idx)=NC;
2 Comments
Atsushi Ueno
on 20 Jun 2021
>Is this correct? ---> Yes, it is correct syntax. No, it does not behave as you expect.
cA = randi(10,[3 10]); i = 1; NC = 5; % temporary value
%if cA(i+1,:) < NC; % 1: No semi-colon, 2: any() is needed, 3: actually if statement is not needed
cA(i+1,cA(i+1,:)<NC) = NC % all of row i+1 of cA is set as NC
%end; % 1: No semi-colon, 3: actually if statement is not needed
Now you are trying the third indexing approach. Please check out it.
>In MATLAB®, there are three primary approaches to accessing array elements based on their location (index) in the array. These approaches are indexing by position, linear indexing, and logical indexing.
- Indexing with Element Positions
- Indexing with a Single Index
- Indexing with Logical Values
> Expressions that include relational operators on arrays, such as A > 0, are true only when every element in the result is nonzero.
if statement is not needed in this question's case, but if you use if statement, you have to know that above specfication of if statement.
0 Comments
See Also
Categories
Find more on Cell Arrays in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!