looping for a function
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Hi, can I apply
[output1, output2] = calculate(b);
in a 3D data such as 80x30x400 data?
2 Comments
Answers (2)
KSSV
on 23 Jun 2021
This is what you are looking for?
[m,n,p] = size(b) ; % b is matrix of size 80x30x400
iwant = zeros(p,2);
for i = 1:p
[output1, output2] = calculate(b(:,:,i));
iwant(i,:) = [output1, output2] ;
end
6 Comments
Walter Roberson
on 23 Jun 2021
This has nothing to do with a missing function.
Your code in drought.m is defined to expect at least four output variables -- otherwise you would have received an error about too many output arguments before you reached the error you did.
Your code in drought.m assigns some value to the first of the output variables it assigns.
However, your code in drought.m does not assign any value to the second of the output variables it assigns.
At the moment we do not have enough information to know whether drought.m never assigns to the second output variable, or if instead it does not assign to the second output variable under some conditions and the conditions happen to be such that it does not assign.
For example,
function [A, B, C] = drought(data)
if any(data(:) < 0 %negative rainfall ??
A = nan; %signal invalid data
return
end
A = mean(data);
B = std(data);
c = var(data);
end
In this example code, B is not assigned to if there are any negative values in the input, and C is never assigned to under any conditions. In this example code it could well be the case that the intention was to assign to C instead of c, but MATLAB doesn't know anything about intentions.
2 Comments
Walter Roberson
on 24 Jun 2021
We have not seen your function drought so it is difficut to say why it is failing.
Could you confirm that it is failing when the input is a 1 x 1 x Something array (such as 1 x 1 x 400) ?
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