How do I solve this equation in MatLab?

Find the area of the region bounded by the hyperbola 9x^2−4y^2=36 and the line x=3.

I cannot find out the proper way to input this into MatLab. It requires trig substitution so I believe the problem stems from there but I am new to MatLab and don't know what I can do to fix it.

Here is my code:

>> syms x

>> EQ = 3*sqrt(x^2-4)

EQ =

3*(x^2 - 4)^(1/2)

>> A = int(EQ,2,3)

A =

log(161 - 72*5^(1/2)) + (9*5^(1/2))/2

>>

Here is the actual answer to the problem:

(9/2)*sqrt(5) - 6*ln((3 + sqrt(5))/2)

Answer 1

[KSSV]

Why worry the final answer is same right?

syms x 
eq = 3*sqrt(x^2-4) ;
A1 = int(eq,2,3) ;
A2 =   (9/2)*sqrt(5) - 6*log((3 + sqrt(5))/2) ;

[double(A1) A2]

ans = 1×2

4.2878 4.2878

[Isaac Hewitt]

Can you explain this more, how is this the same answer?

Yeah I just did this and I have no idea how you did this at all. Please explain what is happening.

[KSSV]

Answer is converted into double from symbolic class.

[Isaac Hewitt]

What does that mean? I just downloaded MatLab for a class a few days ago, I have no idea what that means.

I ask this because in all my calculations

log(161 - 72*5^(1/2)) + (9*5^(1/2))/2 = 7.55445

(9/2)*sqrt(5) - 6*ln((3 + sqrt(5))/2) = 4.28776

[Walter Roberson]

format long g
syms x 
eq = 3*sqrt(x^2-4)

eq = 

A1 = int(eq,2,3)

A1 = 

A2 =   (9/2)*sqrt(5) - 6*log((3 + sqrt(5))/2)

A2 = 
          4.28776399803381

simplify(A1 - A2)

ans = 

double(A1 - A2)

ans = 
       2.3429264568019e-16

log(161 - 72*5^(1/2)) + (9*5^(1/2))/2

ans = 
          4.28776399803129

.... not 7.55445