Assigning nested tables inside a parfor-loop

I use parfor for paralelisation, and create an table as LOG which contains a nested table.

Runing the following code will result in the following Error:

Subscripted assignment dimension mismatch for table variable 'Var2'.

VarTypes={'double','table'};
LOG=table('Size',[1 2],'VariableTypes',VarTypes);

parfor i=1:1                   
    nested_table=table(2,3);
    table_row=table(i,nested_table); 
    LOG(i,:)=table_row;
end

My suboptimal solution is to fill the table before the parfor loop:

But is there a cleaner way?

%create first entry
i=1;
nested_table=table(1,1);
table_row=table(1,nested_table);
LOG=table_row;
%concentrate table with duplicates of this entry
for i=2:10
    LOG=[LOG;table_row];
end

%run in parallel
parfor i=2:10
    
    nested_table=table(5,5);
    table_row=table(i,nested_table);
    
    LOG(i,:)=table_row;
end

Answer 1

[Seth Furman]

Adding to Walter's answer:

The table constructor does not allow specifying the widths of individual variables when preallocating with the 'Size' and 'VariableTypes' parameters. One way we can get around this is to preallocate each variable individually and then call the table constructor.

For example

% Preallocate LOG
Var1 = zeros([3 3]);
Var2 = table('Size',[3 2],'VariableTypes',["double","double"]);
LOG = table(Var1,Var2);

% Populate LOG
for i = 1:10
    nested_table = table(i*2,i*5);
    LOG(i,:) = table(i,nested_table);
end

It's worth noting that, in this toy example, there's no benefit to using a parfor loop. See the following page in the documentation for advice on when to use a parfor loop.

https://www.mathworks.com/help/parallel-computing/decide-when-to-use-parfor.html

Answer 2

[Walter Roberson]

The problem is that

LOG=table('Size',[1 2],'VariableTypes',VarTypes);

is creating LOG.Var2 as a 1 x 0 table, but you are trying to assign in a 1 x 2 table.

If you assign a 1 x 2 table to LOG.Var2 before-hand, then the assignments will function properly.