How to create column headers?
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I have the following code:
months=1:12;
orientation = [0, -90];
row = 1:3;
tilt = [0,10,20,30,40,50,60,70,80,90];
irr = [10,110,120,130,140,150,160,170,180,190];
table.x=tilt;
table.y=irr;
for m=1:length(months)
for o=1:length(orientation)
for r=1:length(row)
disp([m,o,r])
for n=1:length(tilt)
table.x=tilt(n);
table.y=irr(n);
disp(table)
end
end
end
end
How can I have x and y as the column headers instaed of having them noting every element? for example for m=1,0=2,r=3, I want the output to be:
1 2 3
x y
0 10
10 110
20 120
30 130
40 140
50 150
60 160
70 170
80 180
90 190
0 Comments
Accepted Answer
Scott MacKenzie
on 13 Aug 2021
Edited: Scott MacKenzie
on 13 Aug 2021
Something like this will work. I'm only showing the inner for-loop.
fprintf('%6s%6s\n\n', 'x', 'y');
for n=1:length(tilt)
table.x=tilt(n);
table.y=irr(n);
disp([table.x table.y]);
end
Output (last table only):
12 2 3
x y
0 10
10 110
20 120
30 130
40 140
50 150
60 160
70 170
2 Comments
More Answers (1)
Cris LaPierre
on 13 Aug 2021
My preference is to use the table function to create a MATLAB table (data type table instead of structure)
x = [0,10,20,30,40,50,60,70,80,90]';
y = [10,110,120,130,140,150,160,170,180,190]';
data = table(x,y)
However, to stick to the same approach you are using, remove the last loop. I've reduced months and row to limit the output length here.
months=1:1;
orientation = [0, -90];
row = 1:1;
tilt = [0,10,20,30,40,50,60,70,80,90];
irr = [10,110,120,130,140,150,160,170,180,190];
for m=1:length(months)
for o=1:length(orientation)
for r=1:length(row)
disp([m,o,r])
table.x=tilt';
table.y=irr';
disp(["x","y"])
disp([table.x table.y])
end
end
end
To create exactly what you specified, you can use fprintf instead of disp
for m=1:length(months)
for o=1:length(orientation)
for r=1:length(row)
fprintf('%g %g %g',m,o,r)
fprintf('%s %s',"x","y")
table.x=tilt';
table.y=irr';
fprintf('%g %g\n',[table.x table.y]')
end
end
end
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