Competing algorithms for SNR of a image. Which is better?

2 views (last 30 days)
Is either of these methods preferable to the other for finding SNR of a image?
Method 1:
signalImage1 = double('crop image of L2S11.png');
noisyImage = imnoise(signalImage1,'salt & pepper',0.02);
noiseOnlyImage = double(noisyImage) - signalImage1;
SNR = mean2(signalImage1 ./ noiseOnlyImage );
Method 2:
m=mean2('crop image of L2S11.png');
d=double('crop image of L2S11.png');
sd=std(sd);
SNR=m/sd;
Method 3:(this is giving answer in double)
I=imread('crop image of L2S11.png');
sd=im2double(I);
m=mean2('crop image of L2S11.png');
sd1=std(sd);
SNR=m/sd1;

Answers (1)

Jonas Reber
Jonas Reber on 15 Jun 2011
I would go for method 2 (3 is the same?) but wouln't one calculate SNR = mean2(im)/std(im(:))?
  2 Comments
Jim
Jim on 15 Jun 2011
thank u for ur answer
but method 2 gives the answer as 2.326
and method 3 gives the answer in double
which answer we have to take
Jonas Reber
Jonas Reber on 15 Jun 2011
If I do the following:
i = imread('cameraman.tif'); % load sample image
imd = im2double(i);
imdd = double(i);
snr1 = mean2(imd)./std(imd(:));
snr2 = mean2(imdd)./std(imdd(:));
I twice (snr1 and snr2) get 1.9044, don't you?

Sign in to comment.

Products

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!