Since Cody, I dislike for-loops, but your solution is way simpler than my own algorithm. Mission accomplished...
Nevertheless, I would hope for a non-looped piece of code. Let's see in phase 3.
Remove all the consonants
Find all elements less than 0 or greater than 10 and replace them with NaN
Return 'on' or 'off'
Wayfinding 1 - crossing
Wrap a vector, but insert NaN's at the wrap-positions.
Operate on matrices of unequal, yet similar, size
Wayfinding 3 - passed areas
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