Solution Stats
Problem Comments
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29 Comments
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26 older comments
Alex Feinman
on 25 Jan 2012
Another of the classic "check if MATLAB has a function that does this already" problems...
Michael Joslin
on 6 Feb 2012
What about a vector like [2 3 1]? The top solution will still return true because 1^2 is still one but it is not the square of one of the OTHER numbers.
Felix
on 12 Dec 2012
is the Str2func construct really more effective???
Is it possible that this distorts the metric a bit?
Gregoire
on 11 Apr 2014
It is currently impossible to submit a solution for this problem. The web page will never load.
Mattias
on 2 Jan 2015
The problem description states that one of the numbers has to be a square of one of the OTHER numbers. Still, the test suite tests if [1] gives true. I think [1] should give false, or that describtion be modified.
Ramoflaple
on 4 Jul 2015
Agree with Mattias. the length of input vector should be 2 or larger.
Shamma Sultan
on 30 Aug 2016
The difference between test 4 and 5 which returns different answers is the number 36.. but 36 is not a square root of any number of the list in test 4!!
David Verrelli
on 19 Mar 2017
Agree with Mattias: the Test Suite is defective, and not consistent with the problem specification.
Having an input of [1] is OK, but result should be false, as there is no OTHER element to compare the 1 to!
Marco Green
on 11 May 2018
easy
Ryan Klots
on 4 Dec 2018
Fun question!
asa czylabson
on 30 Jan 2019
the word "other" should be ignored in the description...
Harsha Priya Daggubati
on 21 Feb 2019
fun
Mark Sanderson
on 13 Mar 2019
Good question!
Ali
on 15 Nov 2019
Clever problem
Jyothsna Chintala
on 21 Apr 2020
good
Robison Saalfeld
on 7 Jul 2020
The heading reads:
"...a square of one of the OTHER numbers...".
How can the function be expected to return [true] for a = [1]?
It makes no sense.
Lesandu Wenitha Sugathadasa
on 10 Aug 2020
Good question
Abhijeet Deshmukh
on 11 Aug 2020
This problem is very good
yu wang
on 22 Sep 2020
intersect的返回值为一个向量，即使a和b的交集为空集，返回值仍为向量
x=[20:30]
例如：intersect(x.^2,x)
ans =
空的 1×0 double 行向量
所以isvector(intersect(x.^2,x))是错误的
而isempty是判断数组是不是空的，所以isempty可行
Elizabeth Katulka
on 18 Oct 2020
Tough one, but interesting
Leo S
on 30 Nov 2020
I solved it with 2 for-loops, 1 function, 1 if-condition.
It works, but there are more efficient ways apparently
Yunpeng Teng
on 2 Dec 2020
Hey,the demand of this problem declare that "if one " and "the other",so if the intersect of x and x.^2 only have one value of 0 or 1,it may be return false because their squares are themselves, which is not satisfy the condition implied that c and c^2 is not one.
Nicholas Erimias
on 9 Dec 2020
Nice Problem
David Lusk
on 20 Dec 2020
The question asks if one number is the square of one of the OTHER numbers. Test 3 should return false.
Arunika Oyshi
on 3 Feb 2021
Great problem
Filip Novak
on 21 Apr 2021
Nice
T.T.M
on 29 Aug 2021
error in test 7 ! You missed 'd' in function.
fix it!!!!
Dyuman Joshi
on 29 Aug 2021
Error has been fixed.
Jaden Beck
on 10 Nov 2021 at 17:01
Good problem
Solution Comments
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1 Comment
Josh Klueber
on 16 Nov 2021 at 21:38
tricky
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1 Comment
john perkins
on 4 May 2021
very challenging problem!!
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3 Comments
Emoonah McClerklin
on 23 Mar 2021
I don't understand why #4 if false. Can someone help me?
goc3
on 24 Mar 2021
Test case #4 is true, not false, because the vector contains a perfect square and its square root.
Your function is not passing because it overwrites the check variable for each vector element, only actually checking the last value to return the true/false variable. It happened to pass the other four cases because their answers (either false or true) happen to correlate with your check for the last (or only) element in the vector.
Isabella Stellitano
on 26 Oct 2021
GOOD
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2 Comments
Angelo Ricciardi
on 19 Mar 2021
a = [20:30];
assert(isequal(isItSquared(a),false))
Assertion failed.
It should be true because in the array there is 25.
a = [20:30]
a = 20 21 22 23 24 25 26 27 28 29 30
Dyuman Joshi
on 19 Mar 2021
The question asks that whether a perfect square and it's root both are present in the array or not. You have to check for both and not one only.
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1 Comment
Touhidur Rahman
on 1 Nov 2020
Hi,
I verified this code with the given test suite. but the system is not accepting the code as it is.
thanks
TR
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1 Comment
Shuvo Kumar Paul
on 30 Jul 2020
What's wrong with this code? Runs perfectly on my computer.
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1 Comment
文博 李
on 26 May 2021
I didn't see the leading code,so I put my code here to give some inspiration.
Looking forward to a shorter one
b=~isempty(intersect(a,a.^2));
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1 Comment
Raymond MacNeil
on 18 Nov 2019
whoops, don't know how I managed to confuse .^ with .* for a bit there ---I was like, "What's WRONG?"
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1 Comment
Keerty dev Golhani
on 11 Oct 2019
nice
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2 Comments
Hyeokjin Jho
on 2 Mar 2021
You cheater!
Dyuman Joshi
on 2 Mar 2021
This type of cheat/hack answers are no longer allowed.
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2 Comments
Michael Price
on 20 Jul 2019
Good question
Gustavo Morales
on 18 Nov 2019
0 and 1 elements in a will show the bug in your code
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2 Comments
Rudolf Csikja
on 18 Jul 2019
nice one-liner
Gustavo Morales
on 18 Nov 2019
a vector 'a' with elements 0 or 1 will show the bug in your code
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1 Comment
Yuliano Moscoso Yarin
on 16 Apr 2019
cool!
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2 Comments
Natasa
on 1 Feb 2019
Wow! This took me a couple of days to solve, but I did it and I’m very proud! :D
Gustavo Morales
on 18 Nov 2019
Hi. A vector with ones or zeroes as v = [3, 1] will show the bug in your code.
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1 Comment
Steven Belcher
on 29 Jun 2019
Lol
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3 Comments
Myeongseon Choi
on 27 Jun 2018
Test case : a = [20:30] contains a square. but its expected error is false. It should be fixed
Jann B
on 22 Jul 2019
hello,
where do you find a perfect square in [20:30]?
Matthias Kindler
on 4 Feb 2020
Hi Jann B,
25 is a perfect square, no?
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1 Comment
Jafar Mortadha
on 14 Jan 2018
How is the output true if the vector contains only one number? People posting such meaningless solutions: Please have some common sense!
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1 Comment
Oliviero Allan Ceresa Genet
on 11 Nov 2017
easy easy
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2 Comments
Dustin Jones
on 12 Jul 2017
That's better...
Gustavo Morales
on 18 Nov 2019
a vector as v = [3,2,7,0,5] will show you your code's bug
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2 Comments
Dustin Jones
on 12 Jul 2017
a little smaller now
DilRavsh
on 20 Aug 2017
Nice ☺
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1 Comment
Dustin Jones
on 12 Jul 2017
Works
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1 Comment
Dustin Jones
on 12 Jul 2017
just kidding...
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1 Comment
SIVAPRAKASH DANABALASINGAM
on 10 Jan 2017
very easy
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1 Comment
Noriko Hounoki
on 27 Dec 2016
I want to make this code shorter!!
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1 Comment
Noriko Hounoki
on 24 Dec 2016
Case2,a = [20:30],fails.
Others pass.
Why???
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1 Comment
Habeeb Ali
on 23 Dec 2016
in 2 test suite in a=[20:30] , contains 5^2 =25 so it has to be true not false
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1 Comment
Zhang Liang
on 25 Jul 2016
But there seems to be a better choice. Why forgetting ismember?
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2 Comments
Gary Ong
on 10 Jun 2016
Test 2 in the test suite is wrong!
25 is clearly a perfect square.
Matthew Stuckey
on 15 Jun 2016
the problem is to see if a number is the square of another number in the vector. Although 25 is a perfect square, 5 is not included in the vector
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2 Comments
Michael
on 28 Mar 2016
Though it passes the test suite, I feel like I could make this a better way but I am drawing a blank. Any feedback would be appreciated.
Seung Yub Lee
on 3 Dec 2016
good
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3 Comments
prakirt
on 24 Mar 2016
if a = [20:30] the output should be true as 25 is a perfect square, while in the test case output is given to be false.
Michael
on 29 Mar 2016
25 is not a square of any other members of the group. If the group included 5 it would be true.
Dan Po
on 24 Oct 2016
hur dur durrr durr. sqrt(25)==5, not included in givens
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1 Comment
Gouda
on 8 Sep 2015
Yeah, I did it
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2 Comments
Alexander Wickstrom
on 29 Jul 2015
My solution returns false for [20:30]; why not for [6 10 12 14 101]?
Sebastian
on 8 Sep 2015
Instead of a(1):a(end) you should just write a.
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2 Comments
Zhao Dennis
on 29 Mar 2015
Where did I do wrong？
Tim
on 31 Mar 2015
The desired results are not the character strings 'true' and 'false' but the logical values true and false.
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1 Comment
kunal
on 26 Aug 2014
hint ; any and ismember.
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1 Comment
Chandan singh
on 29 Jul 2014
submitted tested solution but still showing error......
L 17 (C 1-3): Parse error at END: usage might be invalid MATLAB syntax.
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2 Comments
Beshir Aman
on 25 Aug 2014
interesting solution... I like it :)
Sebastian
on 8 Sep 2015
I disagree. Almost every problem has a solution wrapped in this function. It's cheating as it hides the complexity of the code from the scoring algorithm. That's why "eval" is not allowed ...
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1 Comment
Kanchibhotla Chandra Sekhar
on 2 Aug 2013
This is the correctly executing in matlab
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1 Comment
Frequency Domain
on 24 Jul 2013
I wonder...if you cheat, why even bother to actually solve the problem?
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1 Comment
Jamie Sargant
on 4 Jun 2013
I have not heard of ismember before, thanks.
As primitive as my solutions are, I learn just as much from reading other peoples as doing the problem itself. Great setup mathworks :)
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1 Comment
Hardajit
on 25 Aug 2012
Code works on Matlab, but not on your test suite?
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1 Comment
Dishant Arora
on 13 Aug 2012
Srtr2func, classic way:)a new thing learned.
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2 Comments
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1 Comment
Charles Brent
on 3 Apr 2012
test case 3 should be 'false'
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1 Comment
Malte Schledjewski
on 5 Mar 2012
it states 'one of the other' numbers, so for a = [1] it should be false
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1 Comment
Ankur Verma
on 9 Feb 2012
Assertion 2. is not correct. vector 'a' return with 6th element as 25 & thts a perfect square.. So it must be true!!
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