In test #1 answer could be [1 4 2 3], couldn't it? It gives tt = 10, same as proposed [1 2 4 3].
You're correct, Jan. Both options give you a minimum time of 10.
Additional test cases have been added.
I think that ones(4) in Test #3 should be eye(4), instead. Also, #1 has to be fixed as Jan pointed out.
The corrections mentioned by Yuichi (and Jan) have been made.
How to proceed with larger matrix (where permutations are too expensive) ?
Should not need the '=' in the 'if j<=t' statement to get the "correct" answer, but that makes the code match the solution in the test suite.
Make a checkerboard matrix
Most nonzero elements in row
Increment a number, given its digits
Volume of a Parallelepiped
Add more zeros
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