Problem 44074. GJam 2017 Kickstart: Parentheses (Small)

This Challenge is derived from GJam 2017 Kickstart Parentheses. This is the first 100 small cases with max L+R<=20.

Google Code Jam 2017 Qualifier is March 7, 2017. Typically four challenges with small and large aspects with 27 hours to complete.

The GJam story is given L left and R right parentheses determine the maximum number of parentheses pairings.

Input: [L,R], the quantity of parentheses types

Output: [V], the maximum number of parentheses pairings

Examples: [L,R] [V]; [3,2] [3]

For the case ()()(, for example, the three balanced groups are () from indexes 1 to 2, () from indexes 3 to 4, and ()() from indexes 1 to 4.

Theory: Brute force permutations and counting will not succeed in a timely manner for L+R=20. Determining the inherent mathematical pattern is usually the best way to succeed in GJam. GJam Kickstart solutions(C++,Python).