Problem 44500. Find the starting index of a consecutive condition

Difficulty:Rate

Given a logical vector v, and a positive integer n, return the smallest index i that satisfies:

all( v(i : i+n-1) ) == true

For Example,

v = logical([0, 1, 1, 0, 0, 1, 1, 1, 1, 1, 0]);
i = consecutiveFind(v, 4);

Then:

i = 6

If there is no sequence of n consecutive true, then i should be an empty array.

Solve

Last Solution submitted on Dec 31, 2024

Atsushi Ueno on 16 Nov 2019

The test suite is not enough because it does not contain any case that the number of consecutive true bits is exactly same as n.

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